Question

using the identity find the value of 101*99​

Answer 1

$101 \times 99$

$= (100 + 1)(100 - 1)$

Now, We know that ,

$(x + y)(x - y) = {x}^{2} - {y}^{2}$

Therefore,

$(100 + 1)(100 - 1)$

$= {100}^{2} - {1}^{2}$

$= 10000 - 1$

$= 9999$

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Answer 2

Answer:

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Step-by-step explanation:

Hi friend!!!!

→101×99.

=(100+1)(100-1).

by using the property (a+b)(a-b)=a²-b²

=(100)²-1

=10000-1

=9999

I hope this will help u ;)