Using the identity for square of a binomial, evaluate : (103) whole square
please give a detailed answer, telling me what happens because of what
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Answer:
(103) ^2
expanding 103 as 100+ 3
(100+ 3)^2
using identity (a+ b)^2= a^2+ b^2 + 2ab
here a = 100
b= 3
100^2+ 3^2 + 2(100)(3)
10000+ 9+ 600
10609
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