Question

using the identity for square of a binomial evaluate
${(701)}^{2}$
​

Answer 1

Answer:

Question:-

▪︎Using the identity for square of a binomial evaluate (701)²

Identity Used:-

▪︎{a+b}²=(a²+2ab+b²)

Solution:-

The no. is expanded as (700+1)

(700+1)²

=>[(700)²+(2×700×1)+(1)²]

=>(4900+1400+1)

=>6301

Hence, the answer is (701)²=6301.

Answer 2

Answer:

(701)^2

( a + b)^2 = ( a^2 + 2ab + b^2 )

= (700)^2 + (2×700×1) + (1)^2

= 4900+1400+1

= 6301

So, (701)^2 is 6301.....❤