Math, asked by pangodusalimpc4anr, 11 months ago

Using the identity
 {a}^{3}  +  {b}^{3}  +  {c}^{3}  - 3abc = ( {a}^{2}  +   {b}^{2}  +  {c}^{2}  - ab - bc - ac)(a + b + c)
multiply
9 {x}^{2}  + 25 {y}^{2}  + 15xy + 12x - 20y + 16
by
3x - 5y - 4

Answers

Answered by triptekade
0

( {9x}^{2}  + 25 {y}^{2}  + 15xy + 12x - 20y + 16) \times (3x - 5y - 4) \\ ( {3x)}^{2}
{{(3x)}^{2}  +  {( - 5y)}^{2}  +  {( - 4)}^{2}  - (3x)( - 5y) - (3x)( - 4) - ( - 5y)( - 4)}{3x  + ( - 5y) + ( - 4)} \\  {(3x)}^{3}  +  {( - 5y)}^{3}  +  {( - 4)}^{3}  - 3(3x)( - 5y)( - 4) \\ 27 {x}^{3}  - 125 {y}^{3}  - 64 - 180xy

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