Question

Using the identity
$(a + {b}^{2}) = ( {a + 2ab}^{2} + {b)}^{2}$
evaluate
1.(94)²
2.(192)²
3.(389)²​

Answer 1

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Answer 2

$(a + b) {}^{2} = a {}^{2} + 2ab + b {}^{2}$

$1)(94) {}^{2} = (90 + 4) {}^{2}$

$(90 + 4) {}^{2} = 90 {}^{2} + 2(90)(4) + 4 {}^{2}$

$2)(192) {}^{2} = (190 + 2) {}^{2}$

$(190 + 2) {}^{2} = 190 {}^{2} + 2(190)(2) + 2 {}^{2}$

$3)(389) {}^{2} = (300 + 89) {}^{2}$

$(300 + 89) {}^{2} = 300 {}^{2} + 2(300)(89) + 89 {}^{2}$

u can evaluate further.....

if u would use (a-b)^2. ......then this would be very easy than (a+b)^2

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