Question

using the kinematic equation​

Answer 1

Answer:

The kinematic formula Δ x = v 0 t + 1 2 a t 2 \Delta x=v_0 t+\dfrac{1}{2}at^2 Δx=v0t+21at2delta, x, equals, v, start subscript, 0, end subscript, t, plus, start fraction, 1, divided by, 2, end fraction, a, t, squared is missing v, so it's the right choice in this case to solve for the acceleration a.

Step-by-step explanation:

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