Question

Using the laws of exponents , find the corrrect path of

the following maze.


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Answer 1

Step-by-step explanation:

Given :-

Given attachment

To find :-

Using the laws of exponents , find the corrrect path of the following maze.

Solution :-

Path:-

First row :-

First circle:

a⁴a⁷

=> a^(4+7)

Since a^m × a^n = a^(m+n)

=> a¹¹

a⁴a⁷ = a¹¹

second circle :

a⁴b⁴

=> (ab)⁴

Since a^m × b^m = (ab)^m

a⁴b⁴ = (ab)⁴

Second row :-

Second circle :

(-b²)⁴

=> (-b)^2×4

Since a^m × a^n = a^(m+n)

=> (-b)⁸

(-b²)⁴ = (-b)⁸

Third circle :-

a⁵×a

=> a^(5+1)

Since a^m × a^n = a^(m+n)

=> a⁶

a⁵ à = a⁶

First row :-

Fourth circle :-

a⁵:a⁴

=> a⁵/a⁴

=>(a)^(5-4)

Since a^m / a^n = a^(m-n)

= > a¹

=> a

a⁵:a⁴ = a

Second row :-

Fourth circle :-

(b⁶:b³)²

=> (b⁶/b³)²

=> (b^(6-3))²

Since a^m / a^n = a^(m-n)

=>(b³)²

=> b^(3×2)

=>b⁶

Since (a^m)^n = a^mn

(b⁶:b³)² = b⁶

Fourth row :-

Fourth circle :-

c³ c^n

=> c^(3+n)

Since a^m × a^n = a^(m+n)

c³ c^n = c^(3+n)

Answer :-

The Path is as follows

first circle in first row ---> second circle in first row --> Second circle in second row ----> Third circle in second row ---->fourth circle in first row ---> fourth circle in second row ----> fourth circle in fourth row-----> laughing symbol

Used formulae:-

• a^m × a^n = a^(m+n)

• a^m / a^n = a^(m-n)

• (a^m)^n = a^mn

• a^m × b^m = (ab)^m

Answer 2

Answer:

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