Question

using the laws of exponents find the value of (3x*9x+1)÷(3x-1*9x-1)​

Answer 1

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$(3x*9x+1)÷(3x-1*9x-1)$

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$(3x*9x+1)÷(3x-1*9x-1)$

$&#8658 ({27x}^{2}+3x)÷({27x}^{2}-9x-3x+1)$

$&#8658 ({27x}^{2}+3x)÷({27x}^{2}-12x+1)$

$&#8658 \frac{({27x}^{2}+3x)}{({27x}^{2}-12x+1)}$

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