Using the measures given in the figure, find the area of ABCD
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In the given fig. ABD is right angled triangle at A,
Given that AB = 40cm, and AD = 9cm
Therefore, the area of triangle ABD
= 180 sqm
Now, the area of triangle, ∆BCD
Now area of quadrilateral ABCD,
= 180 + 390
= 570 sq m
In the given fig. ABD is right angled triangle at A,
Given that AB = 40cm, and AD = 9cm
Therefore, the area of triangle ABD
= 180 sqm
Now, the area of triangle, ∆BCD
Now area of quadrilateral ABCD,
= 180 + 390
= 570 sq m
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