Question

using the method of dimension, check the correctness of the following equation.fs= 1/2 mv²- 1/2 mu², where s is the distance moved by a body of mass m acted upon by a force f, and v being respectively the initial and the final velocities of the body. solve the question in physics
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Answer 1

Explanation:

the dimension of force =[ MLT^-2]

the dimension of distance = [L]

the dimension of mass =[M]

the dimension of velocity= [LT^-1]

so substitute in the equation,

[MLT^-2] [ L] = [M] [LT^-1]^2 - [M] [ LT^-1]^2

(*fractions have no dimensions)

[ML^2 T^-2] = [ML^2 T^-2] - [ML^2 T^-2]

As both sides the dimensions are same ,this equation is dimensionally correct.

(*Note that dimensionally correct does not mean that it is dimensionally equal)