Question

using the method of dimension, check the correctness of yhe equation. F.S=1/2mv2-1/2mu2?

Answer 1

[F]=M.L.T^(-2)
[S]=L
L.H.S.=M.L^2.T^(-2)

R.H.S.=1/2×M.L^2.T^(-2)

L.H.S.=R.H.S.

Answer 2

Answer:

This equation is correct

Explanation:

Given that,

$F.S=\dfrac{1}{2}mv^2-\dfrac{1}{2}mu^2$

L.H.S represent the work and R.H.S represents the change in kinetic energy.

F = force

S = distance

We know that,

M represents of mass, L represents of distance and T represents of time.

Using dimension formula

$[MLT^{-2}][L]=[M][LT^{-1}]^2-[M][LT^{-1}]^2$

$[ML^2T^{-2}]=[ML^2T^{-2}]-[ML^2T^{-2}]$

L.H.S=R.H.S

SO, We can say that this equation is correct.

Hence, This equation is correct