Question

Using the method of dimensions, derive an expression for rate of flow (v) of a liquid through a pipe of radius r under a pressure gradient (p/l). Given that ‘v' also depends on coefficient of viscosity (η) of the liquid.

Answer 1

Answer:

L^3 T^-1

Explanation:

= p r^4 / neta

= (M L^-1 T^-2) L^-4 / (M L^-1 T^-2) ( L)

= L^3 T^-1