Question

using the method of integration derive the equation of motion and find the distance travelled in and nth term​

Answer 1

Answer:

Explanation:

EQUATION 1    V= U+AT

dv/dt=a

dv= a.dt

∫dv = ∫a.dt            for dv limits are ( u to v)      (1)

since a is constant  ( for uniformly accelerated body)

v-u = a∫dt                    for dt limits are (0 to t)

v-u = at

v= u+at hence proved

equation 3      v squre - usquer = 2ax

a= vdv/dx

a.dx= v.dv

∫a.dx=∫v.dv

a∫dx= ∫v.dv                     ( limits for dv= u to v

ax = (v^2- u^2)/2

2ax= v^2-u^2       hence proved                

equation 2     x= ut + 1/2 at squre

v= at                       when u=0

dx/dt = a.dt

dx= dv/dt.dt(.dt)

∫dx=∫dv/dt + ∫a.dt.dt

x= vt+ 1/2 at^2 hence prove

x= vt +

Answer 2

Explanation:

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