Using the molecular orbital energy diagram discuss the magnetic character of O2 molecule
Answers
Answer:
Oxygen molecule {O}_{2}O
2
: The electronic configuration of oxygen (z=8)(z=8) in the ground state is 1{s}^{2}2{s}^{2}2{p}^{4}1s
2
2s
2
2p
4
. Each oxygen atom has 88 electrons, hence in {O}_{2}O
2
molecule there are 1616 electrons.
Therefore, the electronic configuration of {O}_{2}O
2
is as follows :
{ O }_{ 2 }:KK{ \left( { \sigma }_{ 2s } \right) }^{ 2 }{ \left( { { \sigma }_{ 2s } }^{ \bullet } \right) }^{ 2 }{ \left( { { \pi }_{ 2p } }_{ x } \right) }^{ 2 }={ \left( { { \pi }_{ 2p } }_{ y } \right) }^{ 2 }{ \left( { { \pi }_{ 2p } }_{ x } \right) }^{ 1 }={ \left( { { { \pi }_{ 2p } }_{ y } }^{ \bullet } \right) }^{ 1 }O
2
:KK(σ
2s
)
2
(σ
2s
∙
)
2
(π
2p
x
)
2
=(π
2p
y
)
2
(π
2p
x
)
1
=(π
2p
y
∙
)
1
The molecular orbital energy level diagram of oxygen molecule is given as follows :
Bond order \cfrac { { N }_{ b }-{ N }_{ a } }{ 2 } =\cfrac { 8-4 }{ 2 } =2
2
N
b
−N
a
=
2
8−4
=2
Thus, oxygen molecule has two bonds. i.e., one is bond and one p bond. The last two electrons in { p }_{ 2px }^{\bullet}p
2px
∙
and { p }_{ 2py }^{ \bullet }p
2py
∙
orbitals will remain unpaired. Therefore, oxygen molecule has paramagnetic character due to the presence of two unpaired electrons.
Explanation: