Using the oxidation numbers method of the net ionic equation for the reaction of potassium permanganate KMno4 with ferrous sulphate FeSO4
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Answer:
MnO4^- + 8H+ + 5Fe^2+ = 5Fe^3+ +Mn^2+ + 4H20
Explanation:
Assuming KMno4 is in acidic medium
Mno4^- = Mn2+
7=2 (decreases by 5)
Fe2+ = Fe3+
2=3 (increases by 1) ×5
Now it is
Mno4- + 5Fe2+. = Mn2+. + 5Fe3+
now add h20 to oxygen deficient side
Mno4- + 5Fe2+. = Mn2+. + 5Fe3+ + 4H20
now add H+ in hydrogen deficient side
Mno4- + 5Fe2+. + 8H+= Mn2+. + 5Fe3+ +4H20
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