Question

Using the proper identity, find the value of (x² + 4)2 + (x² - 4) 2+ 16x2.​

Answer 1

Answer:

You can factor that (x²-4) in (x-2)(x+2) so the equation becomes

(x-2)(x+2)/(x-2) = (x+2)

Now, Write the restrictions of domain: x≠2

Find the highest common denominator: (x-2) and rewrite the equation

(x-2)(x+2)/(x-2) = (x+2)(x-2)/(x-2)

Multiply each term by (x-2) and simplify to get:

(x-2)(x+2)= (x+2)(x-2) which are differences of squares so, simplifying once again, you get:

x² -4 = x² -4

x² - x² = -4+4

0=0

Which means this equation is always true EXCEPT for the value of 2.