Question

Using the proper identity,find the value of (x²+4²) + (x² - 4)² + 16x².​

Answer 1

Answer:

$({ {x}^{2} } + 4^{2} ) + ( { {x}^{2} - 4) }^{2} \\ + {16x}^{2}$

${x}^{2} + {4}^{2} + { {x}^{2} }^{2} + 16 - {8x}^{2} + 32$

${ {x}^{2} }^{2} + {x}^{2} + {8x}^{2} + 32$

${ {x}^{2} }^{2} + {9x}^{2} + 32$