Question

using the proper identity... please find the answer and tell me I am in difficult times​

Answer 1

Answer:

Here u can use the identity $(a+b)^{2}$ = $a^{2} +b^{2} + 2ab$

Step-by-step explanation:

(5x + 8)^2 - 160x = (5x-8)^2

⇒25$x^{2}$ + 64 + 80x - 160x = 25$x^{2}$ + 64 - 80x

(25$x^{2}$ is cancelled on both the sides )

⇒ 64-80x = 64 - 80x

Since LHS = RHS

the statement is true (verified)

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