Question

using the property of sum find the sum of first 6 odd number​

Answer 1

Answer:

36

Step-by-step explanation:

1+3+5+7+9+11=36 the sum of first 6 odd number

Answer 2

Given : first 6 odd number​

To Find :  the sum

Solution:

Property :

Sum of first n odd natural number  = n²

to find sum of first 6 odd number​

use n = 6

Hence sum = 6²  = 36

1 + 3 + 5 + 7 + 9 + 11  = 36

Using AP

a = 1

d = 2

n = 6

Sum  = (n/2)(2a + (n-1)d)

= (6/2)(2 * 1 + (6 - 1) * 2)

= 3( 2 + 10)

= 3(12)

= 36

Hence the sum of first 6 odd natural  number​s  is 36

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