using the propoties of proportion solve for x (√7x + √4x-3)/(√7x - √4x-3)
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= √[(7x2 + 2 √(14)x + 2)/(x2 - x/2 + 1/16)]
(7x2 + 2 √(14)x + 2)
First let us find the factors of the quadratic equation in the numerator.
(x2 - x/2 + 1/16)
= (4x + 1) (4x + 1)
= √[(7x + √14)(7x + √14) / (4x + 1) (4x + 1)]
= |(7x + √14)/(4x + 1)|
hope it is helpful
.
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