Question

using the Pythagoras theorem find the hypotensue of a right angeld triangle who sides 48cmand 55cm​

Answer 1

Answer:

Here's your answer

Let the triangle have vertices A, B and C( Diagram in attachment )

‌C

/ ।

/ ।

/_ । A

B

AB = 48cm

CB = 50cm

Since the triangle is a right angled triangle , the side AC can be found by using the PYTHAGORAS THEOREM

So,

(AB)² + (AC)² = (CB)²

(48)² + (AC)² = (50)²

(AC)² = (50)² - (48)²

(AC)² = 2500 - 2304

(AC)² = 196

ac = \sqrt{196}ac=

196

AC = 14cm

since it is a right angled triangle ,in which AC is perpendicular to the base , it will be the height

So,

Base = 48cm

Height = 14cm

Area of triangle = ½ × base × height

= \frac{1}{2} \times 48 \times 14=

2

1

×48×14

= 336cm²

So,

the area of triangle is 336cm²

Answer 2

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