Question

Using the quadratic formula to solve 4x2 – 3x + 9 = 2x + 1, what are the values of x?

Answer 1

answer in attachment
hope it is useful

Answer 2

Answer-

The values of x are,

$\dfrac{5+ \sqrt{103}\ i}{8},\ \dfrac{5-\sqrt{103}\ i}{8}$

Solution-

Here given,

$\Rightarrow 4x^2-3x + 9 = 2x + 1$

$\Rightarrow 4x^2-5x + 8 =0$

Here,

$a=4,\ b=-5,\ c=8$

Then,

$x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}$

$=\dfrac{5\pm \sqrt{(-5)^2-4\times 4\times 8}}{2\times 4}$

$=\dfrac{5\pm \sqrt{25-128}}{8}$

$=\dfrac{5\pm \sqrt{-103}}{8}$

$=\dfrac{5\pm \sqrt{103}\ i}{8}$

$=\dfrac{5+ \sqrt{103}\ i}{8},\ \dfrac{5-\sqrt{103}\ i}{8}$