Question

Using the quadratic formula to solve 4x2 – 3x + 9 = 2x + 1, what are the values of x?

Answer 1

Answer:

x=\frac{5+i\sqrt{103}}{8}

x=\frac{5-i\sqrt{103}}{8}

Step-by-step explanation:

ax^{2} +bx+c=0  is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}}{2a}

in this problem we have

4x^{2}-3x+9=2x+1    

4x^{2}-3x+9-2x-1=0    

4x^{2}-5x+8=0    

a=4\ b=-5\ c=8

substitute in the formula

x=\frac{-(-5)(+/-)\sqrt{(-5)^{2}-4(4)(8)}}{2*4}

x=\frac{5(+/-)\sqrt{25-128}}{8}

x=\frac{5(+/-)\sqrt{-103}}{8}

remember that

i=\sqrt{-1}

x=\frac{5(+/-)i\sqrt{103}}{8}

Answer 2

Answer:

The answer is C

Step-by-step explanation: