Question

Using the quadratic formula to solve x2 + 20 = 2x, what are the values of x?
1 plus-or-minus StartRoot 21 EndRoot i
Negative 1 plus-or-minus StartRoot 19 EndRoot i
1 plus-or-minus 2 StartRoot 19 EndRoot i
1 plus-or-minus StartRoot 19 EndRoot i

Answer 1

Answer:

Step-by-step explanation:

Here,

b^2-4ac=4-4*1*20

=-76

Thus as ans is in negative

It don't have real roots

Answer 2

Answer:

$x = 1 \pm \sqr{19}i$

Step-by-step explanation:

Given :$x^2+20=2x$

To Find : Solve using quadratic formula .

Solution :

Formula :$x = \frac{-b\pm \sqrt{b^2-4ac}}{2a}$

Equation : $x^2+20=2x$

$x^2+20-2x=0$

a = 1

b = -2

c = 20

Substitute the value in formula

$x = \frac{-(-2)\pm \sqrt{(-2)^2-4(1)(20)}}{2}$

$x = 1 \pm \sqr{19}i$

Hence the value of x is $x = 1 \pm \sqr{19}i$