Question

Using the rearrangement property find the sum-
4/3+3/5+(-2/3)+(-11/5)

Answer 1

Solution

$( \frac{4}{3} - \frac{2}{3} ) + ( \frac{3}{5} - \frac{11}{5} ) \\ = \frac{2}{3} - \frac{8}{5} \\ = \frac{10 - 24}{15} \\ = \frac{ - 14}{15}$
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#Amrit⭐

Answer 2

Concept

The numbers in an additional statement can be rearranged and grouped in any order, according to the Rearrangement property.

Given

The given problem is 4/3+3/5+(-2/3)+(-11/5).

To find

We have to find the sum by rearrangement property.

Solution

Numbers with the same denominator are grouped together.

$\left(\frac{4}{3}+\frac{-2}{3}\right)+\left(\frac{3}{5}+\frac{-11}{5}\right) \\=\left(\frac{4+(-2)}{3}\right)+\left(\frac{3+(-11)}{5}\right) \\=\left(\frac{2}{3}\right)+\left(\frac{-8}{5}\right)$

Now, we take LCM of 3 and 5=15

$=\left(\frac{2}{3}\right)+\left(\frac{-8}{5}\right) \\=\left(\frac{10}{15}\right)+\left(\frac{-8}{5}\right) \\=\frac{10+(-24)}{15} \\\=\frac{-14}{15}$

$=\frac{-14}{15}$