Using the remainder and factor theorem, factorise the following polynomial
X raise to 3 + 10X raise to 2 - 37x + 26
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Let f(x) = x3 + 10x2 – 37x + 26.
Putting x = 1, we get.
f(1) = 1 + 10 - 37 + 26 = 0.
∴ By factor theorem, x - 1 is factor of f(x).
On dividing x3 + 10x2 – 37x + 26 by x – 1, we get x2 + 11x – 26 as the quotient and remainder = 0.
∴ The other factor of f(x) are the factor of x2 + 11x - 26.
Now, x2 + 11x - 26.
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