Using the remainder theorem ,find the remainder when:
(3x^4-6x^2-8x+2) is divided by (x-2)
Answers
Answered by
16
Step-by-step explanation:
let p(x)=3x⁴-6x²-8x+3
q(x)=x-2
x-2=0
x=2
now using remainder theorem
=3(2)⁴-6(2)²-8(2)+2
=3(16)-6(4)-16+2
=48-24-16+2
=10
10 is the remainder
Answered by
3
Answer:
10
Step-by-step explanation:
x-2=0
x=0+2=2.
By the remainder theorem,we know that when f(x) is divided by (x-2),the remainder is f(2).
Now, f(2) = (3×2^4-6×2^2-8×2+2)
= 3×16-6×4-16+2
= 48-24-16+2
= 50-24-16
= 10.
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