Question

Using the remainder theorem ,find the remainder when:

(3x^4-6x^2-8x+2) is divided by (x-2)​

Answer 1

Step-by-step explanation:

let p(x)=3x⁴-6x²-8x+3

q(x)=x-2

x-2=0

x=2

now using remainder theorem

=3(2)⁴-6(2)²-8(2)+2

=3(16)-6(4)-16+2

=48-24-16+2

=10

10 is the remainder

Answer 2

Answer:

10

Step-by-step explanation:

x-2=0

x=0+2=2.

By the remainder theorem,we know that when f(x) is divided by (x-2),the remainder is f(2).

Now, f(2) = (3×2^4-6×2^2-8×2+2)

= 3×16-6×4-16+2

= 48-24-16+2

= 50-24-16

= 10.