Using the remainder theorem, find the remainder, when p(x) is divided by g(x) where p(x) = 23+32−11−3 and g(x) = (+1/2).
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Answer:
p(x)=x3−6x2+2x−4 and
g(x)=1−23x
1−23x=0
=>23x=1
=>x=32
By, remainder theorem, the remainder when p(x) divided by g(x) is p(32)
Thus,
p(32)=(32)3−6(32)2+2(32)−4
=278−96×4+34−4
=278−98+34−
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