Question

Using the remainder theorem find the remainder when p(x) is divided by g(x) where p(x)=x^3-6x^2+9x+3 g(x) = x-1

Answer 1

Put x=1 in the equation
1^3-6×1^2+9×1+3=9

Answer 2

Put X =1
p (1) = 1^3 - 6 × 1^2 + 9×1 + 3
=7