using the remainder theorem, find the remainder when x^3 +4x^2 -3x +10 is divided by (x-4)
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1
Answer:
x-4=0
x=4
p(4)=(4)^3+4×(4)^2-3×4+10
64+64-12+10=126
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Question: Using the remainder theorem, fine the remainder when x³ + 4x² - 3x + 10 is divided by (x-4)
ANSWER: Using remainder theorem, we get
p(x) = x³ + 4x²0 -3x + 10 (here x will be 4 ; x = 4)
p(4) = (4)³ + 4(4)² - 3(4) +10 (putting the value of x = 4)
p(4) = 64 + 64 - 12 + 10
p(4) = 138 - 12
p(4) = 126
therefore, remainder of equation x³ + 4x² - 3x + 10 is 126
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