using the remainder theorm find the remainder obtained when x cube +(kx+8)x+k is divided by x+1 and x-2 Hence find k if the sum of the two remainder is 1
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Step-by-step explanation:
X+1=> x=-1 , x+2=> x=-2
Substitute x=-1 in the equation , we will get,
2k-9 as remainder
Now substitute x=-2 in the equation , we will get , 5k-24 as remainder
Now it its given that sum of the remainder is 1 so,
(2k-9)+(5k-24)= 1
=>(2k-9)=-(5k-24)
=> 2k-9= -5k+24
=>2k+5k=24+9
=>7k=33
K=33/7 or k = 4*(5/7)
Megarox:
Wait I did one thing wrong it is 8x so just multiply 8(-1) and 8(-2)
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