using the remainder theroem when y³-7y²+15y-19 is divided by (y-3)
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Answer:
here , p (y) = y^3 - 7y^2 + 15y -19, and the zero of y-3 = 3.
Step-by-step explanation:
p (3) = 3^3 - 7 (3^2) + 15(3) -19
= 27 - 7(9) + 45 -19
= 27 - 63 + 45 -19
= -10 .
Answer : -10.
Answered by
1
Hence the remainder is -10.
Hope it helps......^•^
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