Question

using the reminder theorem, find the reminder,when p( x)= x-1.​

Answer 1

Answer:

x-1=0

x=1

putting value of x in p(x),we get

=(1)³ -6×(1)² -9×1+3

=1–6×1–9+3

=1–6–6

=1–12

=–11

Hence, Remainder is = –11