Using the standard electrode potential, find out the pair
between which redox reaction is not feasible.
Eϴ values: Fe³⁺/ Fe²⁺ = + 0.77; I₂/I⁻ = + 0.54;
Cu²⁺ / Cu = +0.34; Ag⁺ / Ag = + 0.80 V
(a) Fe³⁺ and I⁻ (b) Ag⁺ and Cu
(c) Fe³⁺ and Cu (d) Ag and Fe³⁺
Determine the E°cell of the four redox reactions. If the value
of E°cell of a reaction is negative, that reaction will not take
place.
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option c Should ve correct .....
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The redox reaction which is not feasible is between
(d) Ag and Fe³⁺
- The E cell value of a cell is the electromotive force between two half cells
- The higher the E cell value the more easier the reaction proceeds.
- E cell = E oxidation - E reduction
- For 1) E cell = 0.77-0.54 =0.23
- 2) E cell = 0.80-0.34 = 0.46
- 3) E cell = 0.77 - 0.34 = 0.43
- 4 ) E cell = 0.77-0.80 = -0.3
- Therefore 4) has negative E cell value, so it is not feasible.
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