Question

Using the standard formulae, expand each of the following

2.
(1) (2a +3b)​

Answer 1

Answer:

We need to expand (2a−3b)

3

We know suitable identity is (x−y)

3

=x

3

−3x

2

y+3xy

2

+y

3

Here x=2a and y=3b

Therefore, value of (2a−3b)

3

is

=(2a)

3

−3(2a)

2

(3b)+3(2a)(3b)

2

−(3b)

3

=8a

3

−36a

2

b+54ab

2

−27b

Step-by-step explanation:

I am not sure that this is the perfect answer....

sorry...

Answer 2

Answer:

Step-by-step explanation:

we use identity here,

(a-b)^2 = a^2 -2ab +b^2