Question

.using the subsidiary quantum number, write out the electronic configuration of the first 30 element

Answer 1

Answer:

All of these shells are filled except the 3p shell which has four electrons. Therefore, the electronic configuration of sulfur can be written as 1s2 2s2 2p6 3s2 3p4.

Explanation:

Answer 2

Answer:

Explanation:

Hydrogen

H

1

1s1

Helium

He

2

1s2

Lithium

Li

3

1s2 2s1

Beryllium

Be

4

1s2 2s2

Boron

B

5

1s2 2s2 2p1

Carbon  

C

6

1s2 2s2 2p2

Nitrogen

N

7

1s2 2s2 2p3

Oxygen

O

8

1s2 2s2 2p4

Fluorine

F

9

1s2 2s2 2p5

Neon

Ne

10

1s2 2s2 2p6

Sodium

Na

11

[Ne] 3s1

Magnesium

Mg

12

[Ne] 3s2

Aluminium

Al

13

[Ne] 3s2 3p1

Silicon

Si

14

[Ne] 3s2 3p2

Phosphorus

P

15

[Ne] 3s2 3p3

Sulfur

S

16

[Ne] 3s2 3p4

Chlorine

Cl

17

[Ne] 3s2 3p5

Argon

Ar

18

[Ne] 3s2 3p6

Potassium

K

19

[Ar] 4s1

Calcium

Ca

20

[Ar] 4s2

Scandium

Sc

21

[Ar] 3d1 4s2

Titanium

Ti

22

[Ar] 3d2 4s2

Vanadium

V

23

[Ar] 3d3 4s2

Chromium

Cr

24

[Ar] 3d5 4s1

Manganese

Mg

25

[Ar] 3d5 4s2

Iron

Fe

26

[Ar] 3d6 4s2

Cobalt

Co

27

[Ar] 3d7 4s2

Nickle

Ni

28

[Ar] 3d8 4s2

Copper

Cu

29

[Ar] 3d10 4s1

Zinc

Zn

30

[Ar] 3d10 4s2