Question

using the suitable identity evaluate the following: 999²....i will mark brainliest for the correct answer plz​

Answer 1

Answer:

998001

Step-by-step explanation:

(1000-1)^2

(a-b)^2 = a^2 - 2ab +b^2

= 1000^2 - 2*1000*1 + 1^2

= 1000000 - 2000 + 1

= 998001

Answer 2

999^2

Well 999 can be written as 1000 - 1

So

999^2 = (1000 - 1)^2

Using identity

${(x - y)}^{2} = {x}^{2} + {y}^{2} - 2xy$

(1000 - 1)^2 = 1000^2 + 1^2 - 2× 1000 × 1

(1000 - 1)^2 = 1000000 + 1 - 2000

(1000 - 1)^2 = 100001 - 2000

(1000 - 1)^2 = 998,001

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