Question

using the suitable identity expand
(2x - 2√2y)^2
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Answer 1

Answer:

Now using identity (a-b)^2 =a^2+b^2-2*a*b

We have

$(2x - 2\sqrt[]{2}y ) {}^{2}$

$(2x) {}^{2} + (2 \sqrt[]{2}y) {}^{2} - 2 \times 2x \times 2\sqrt[]{2}y$

4x^2+8y^2-8

$4x^2+8y^2-8 \sqrt{2} xy$

Answer thanks

Answer 2

hope this answer helps