Math, asked by harneet052, 4 months ago

using the suitable identity find (2a+3b) (2a-b)​

Answers

Answered by shivamyadav28
2

Answer:

by using (x+a)(x+b)=x^2+(a+b)x +ab

we get

(2a)^2 +(3b-b)(2a)+3b(-b)

4a^2 +4ab-3b^2

Answered by Anonymous
2

Answer:

 \:  \: using \:  \: this \:  \: identity \: \\ (x + a  )(x + b) =  {x}^{2}  + x(a + b) + ab \\ (2a + 3b)(2a - b) = (2a {)}^{2}  + 2a(3b + ( - b)) + 3b \times ( - b) \\  = 4 {a}^{2}  + 2a(3b - b) + ( - 3 {b}^{2} ) \\  = 4 {a}^{2}  + 2a \times 2b  - 3 {b}^{2}  \\  = 4 {a}^{2}  + 4ab - 3 {b}^{2}

I hope it will help you

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