using the Suitable identity find the Square
i (0.4p -0.5q) ^2
ii 95×103
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Here,
Here,x = 100
Here,x = 100a = -5
Here,x = 100a = -5b = 3
Here,x = 100a = -5b = 3Therefore,
Here,x = 100a = -5b = 3Therefore,(100 - 5) \times (100 + 3) = 100^2 + ( - 5 + 3)100 + (-5)(3)\\\\(100 - 5) \times (100 + 3) = 10000 -200 -15\\\\(100 - 5) \times (100 + 3) = 9785
Here,x = 100a = -5b = 3Therefore,(100 - 5) \times (100 + 3) = 100^2 + ( - 5 + 3)100 + (-5)(3)\\\\(100 - 5) \times (100 + 3) = 10000 -200 -15\\\\(100 - 5) \times (100 + 3) = 9785Thus 95 x 103 using identities is 9785
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