Question

Using the transpose method, solve each of the following equation.
(1) 4(x–5)= 8
(2) 3(x+2)=9(x–6)​

Answer 1

Answer:

1)

4(x-5) = 8

x-5 = 8 / 4

x - 5 = 2

x = 5 + 2

x = 7

2)

3(x+2) = 9(x-6)

x + 2 = 9(x - 6) / 3

x + 2 = 3 (x-6)

x + 2 = 3x - 18

3x - x = 2 + 18

2x = 20

x = 10

Hope it helps.

Answer 2

Answer:

1.X=7

2.x=10

Step-by-step explanation:

1.4x-20=8

4x=8+20

4x=28

x=7

2. 3x+6=9x-54

3x-9x= -54-6

-6x=-60

x=10