Question

Using the Venn diagram, verify
n (AUB) = n(A) + n(B) - n(ANB).(​

Answer 1

Answer:

n(AUB)=8

n(A)=5

n(B)=5

n(A intersection B)=2

8=5+5-2

8=10-2

8=8

Answer 2

$n(A\cup B)=8$

$n(A)=5$

$n(B)=5$

$n(A\cap B)=2$

So

$n(A\cup B)=n(A)+n(B)-n(A\cap B)$

$8=5+5-2$

$8=8$

$LHS=RHS$

Hence proved

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