using third equation of motion obtain an expression for maximum height attained by the projected body
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¤ 2aS=Vf^2-Vi^2>>>>>
2gh=Vf^2-Vi^2==== h=Vf^2-Vi^2/ 2g
2gh=Vf^2-Vi^2==== h=Vf^2-Vi^2/ 2g
Bhavishya7:
sorry but I didn't get....can u explain in the terms of 9th grade?
sorry but I didn't get....can u explain in the terms of 9th grade?
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