Using truth table, show that
~(p → ~q) = p^q.
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Step-by-step explanation:
p->q =~p v q
~(p->~q) = ~(~p v ~q ) =~(~p) ^~(~q)
=p^q
_________________________
p q ~q p->~q ~(p->~q) p^q
_________________________
T T F F T T
T F T T F F
F T F T F F
F F T T F F
last 2 columns values are same so
~(p-> ~q) = p^q
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