Question

Using truth tables prove the following logical equivalences.
p→(q→p) ≡ ~p→(p→q)​

Answer 1

Answer:

We know that,

P= T T F F

Q=T F T F

It is given that,

P–>(q–>p)=~p–>(p–>q)

Take LHS

As, p–>(q–>p)

Now, on solving we get,

P–>(q–>p)= T T T T

It is a tautology.......

And take RHS,

~p–>(p–>q)

On solving u get,

~p–>(p–>q)= T T T T

It is also a tautology....

So they are equal...

Hence proved.....

Step-by-step explanation:

Hope it helps you frnd.........