Math, asked by ap6060179, 5 months ago

using using suitable identity find 1)96^2
2)231^2- 131^2​

Answers

Answered by veerasharma2006
2

Answer:

ok

Step-by-step explanation:

1) 96^2

=> (100-4) ^2

=> 100^2+4^2-2*100*4

=> 10000+8-800

=> 9208

2) 231^2-131^2

=> ((200+31)^2)-((100+31)^2)

=> (200^2+31^2+2*200*31)-(100^2+31^2+2*31*100)

=> (400+62+12400)-(10000+62+6200)

=> 12862-16262

=> -3400

MARK AS BRAINLIST, N PLZ DO THANK ALL MY ANSWERS DEAR

Similar questions