Using vectors prove that a quadrilateral is a rectangle if and only if its diagonals are congruent and bisect each other.
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Answer:
Using vectors a quadrilateral is a rectangle if and only if its diagonals are congruent and bisect each other.
Step-by-step explanation:
Let ABCD be a quadrilateral
This quadrilateral is square.
so |AB| = |BC| = |CD| = |DA|
Now
|CD| = |DC|
|DA| = |AD|
the diagnoal are AC and DB
it is square.
then the diagonals bisect each other
We have to prove that AC ⊥ DB
From square law of addition
We know that,
AC = AB+AD and
DB = AB-AD
To prove that AC⊥DB ⇒AC · DB = 0
So,
AC . DB = ( AB + AD) . (AB - AD)
We know that,
(a + b)(a - b) = |a|² - |b|²
⇒AC.DB = |AC|² - |AD|²
Since, ABCD is a square
So,
⇒|AB| = |AD|
⇒ AC.DB = 0
⇒AC ⊥ DB
Hence proved.
Answered by
7
ANSWER:
Hence a quadrilateral is a rectangle if its diagonals are congruent and bisect each other.
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