Question

using VECTORS prove that the angel between the surface of an inclined plane and the horizontal (thr angle of an inclination) is equal to the angel between the normal to thr surface of the inclined plane and vertical​

Answer 1

Answer:

As it is asked for the minimum force required to push the body up the incline plane. it must be equal to the net maximum force acting along the plane of incline.

So from the free body diagram, net force along the incline surface is μmgcosθ−mgsinθ

So $$F >= μmgcosθ−mgsinθ$$

∴F

min

=μmgcosθ−mgsinθ

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Answer 2

Explanation:

the surface of an inclined plane and the horizontal (thr angle of an inclination) is equal to the angel between the normal to thr surface of the inclined plane and vertical .This is circular and perpendicular