Question

using velocity time graph derive the relation v²-u²=2as

Answer 1

graph for derivation

we know : displacement = area under the velocity time graph .

S= area of trapezium ACEF

S= 1/2 ( b¹ + b² ) h

s= 1/2 ( AF+CE )FE

S= 1/2 ( U+ V) T

We know -v= u+ at

v-u/a= t

now 2 in 1

S= 1/2( v+u) (v-u)

2as= ( v+u) (v-u)

2as=v²-u²

[v² - u2 = 2as]