Question

using vesper theory lone pair in pcl5 IF5 sof4 XeoF4​

Answer 1

Answer:

pcl5..... 0 is answer

IF5....... 1 is answer

XeOF4......................5 is answer

Answer 2

Answer:

The total number of lone pairs in  $PC{l_5} \hfill$ is 15.

The total number of lone pairs in $I{F_5}$ is 16.

The total number of lone pairs in $SO{F_4}$ is 14.

The total number of lone pairs in $XeO{F_4}$ is 15.

Explanation:

Total number of lone pairs in $PC{l_5} \hfill$

Since phosphorous is making 5 bonds with 5 chlorine, therefore, phosphorous has 0 lone pairs

5 Chlorine sharing its 1 electron each, therefore, the total number of lone pairs on 5 chlorine is 15.

Therefore, the total number of lone pairs in  $PC{l_5} \hfill$ is 15.

Total number of lone pairs in  $I{F_5}$

Since iodine is making 5 bonds with 5 fluorine, therefore, iodine has 1 lone pair

5 Fluorine sharing its 1 electron each, therefore, the total number of lone pairs on 5 fluorine is 15.

Therefore, the total number of lone pairs in $I{F_5}$ is 16.

Total number of lone pairs in  $SO{F_4}$

Since sulfur is making 6 bonds with 4 fluorine and 1 oxygen, therefore, sulfur has 0 lone pair.

4 Fluorine sharing its 1 electron each, therefore, the total number of lone pairs on 4 fluorine is 12.

One oxygen shares its 2 electrons, therefore, the total number of lone pairs of oxygen is 2

Therefore, the total number of lone pairs in $SO{F_4}$ is 14.

Total number of lone pairs in $XeO{F_4}$

Since xenon is making 6 bonds with 4 fluorine and 1 oxygen, therefore, xenon has 1 lone pair.

4 Fluorine sharing its 1 electron each, therefore, the total number of lone pairs on 4 fluorine is 12.

One oxygen shares its 2 electrons, therefore, the total number of lone pairs of oxygen is 2

Therefore, the total number of lone pairs in $XeO{F_4}$ is 15.